That'S just the x axis, and then we have this constant flat line. ![]() This on the left side would be y equals 3 times the natural log of negative x, and we got y equals 0. This curve here will be y equals 3 times the natural log of x. Has a density of 62.4 per cubic foot, so we have this taint shaped like this bounded by these curves. NOTE: Inertia forces are considered to operate through the centroid of the dam section.Find the hydrostatic force on the flat vertical side of a tank that has the shape of the region bounded by y equals 0 y equals 3 l n x y equals 3 l n of negative x and y equals 3 l n of 17 point water. : basic seismic coefficient taken from seismic maps. Seismic forces are estimated according to the following equations:Īnd : horizontal and vertical seismic coefficient So, the generated dynamic loads are due to the inertia of the dam and hydrodynamic forces by the water in the reservoir. Seismic vibration influence both dam body and water in the reservoir of the dam. The horizontal component has greater effect. ![]() However, it has to be resolved into vertical and horizontal components for the design purposes. Uplift is generally reduced by constructing drainage pipes between dam and its foundation, constructing cut off walls under the upstream face, holes in the dam section, or pressure grouting the dame foundation.ĭynamic loads created due to earthquakes must be considered in the design of all major dams located in ‘high-risk’ seismic regions, and for dams situated in close proximity to potentially active geological fault complexes.Įarthquake produces waves in every possible direction. This total uplift acts at B/3 from the heel or upstream end of the dam. Where is the uplift pressure, B is the base width of the dam and H is the height up to which water is stored. With reference to figure 3, uplift pressure is given by
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